Hello from cold Russia.
1)Don't use the grounding wire to connect N pin on your wall switch. If you don't want to win Darwin award.
Look at the first picture.
2)Use capasitors to connect the switch and the bulb.
Look at the second picture.
C1 - Capacity. Metal-film capacitor for 400 volts.
It works as a "quenching capacitor" or "resistance". In order for the "part of the current" to remain on the switch and feed it, in the switched on position of the key.
C2 - Capacity. Metal-film capacitor for 400 volts.
Works as a "bypass" resistor. Serves to ensure that energy-saving gas-discharge or LED lamps do not blink (from the current passing through them supplying the switch) in the off position of the key.
Hey this solution would help me in some installations, do you have more info (or copy and paste the text so we can translate.) thanks!
Use LED or GAS lamps only. Only low power consumtion devices.
First column - "Type of bulb"
P1 - power of BULB in WATTS.
C1 - quenching capacitor - 1,5 micro Farades to 3,3.
C2 - 0.47 micro Farades. (that solution is need if your LED lamp is cheap, there are a lot of expensive bulbs witch have that solution included). Only cheap bulbs blink.
Hi, can you share the formula that you use to calculate the capacitors? For example, what should be the capacitor 1 and 2 in case the load is LED lighting with transformers, about 40W total?
Thanks a lot!
I don't have formula. Experimentally - U'll need 7-10 micro Farades capacitor for that solution.
I guess that means -- two 4,7 micro Farades capacitors. Parallel connection.
Hi, has anyone else tried this? This will be great if it works, my question is how will this work when I have 4 lights in the circuit, these are 12W LED dimmable lights (dimmable by turning them on and off and the lights have 4 brightness settings).
Will I need to change the capacitor sizes?
Hi, i don't think that this solution wil work with dimmable lights. It is not good idea. This solution is only for LED or GAS lamps only.
Am I right that provided solution is based on the fact that the value of current through the switch is very low?That's why the lamp (if it's cheap) can just blink in the off position of switch.
One more question - is that required that you have to break the "Line" instead of "Neutral"? Because usually switches break the "Neutral".